(7x+2)(2x^2-5x-3)=0

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Solution for (7x+2)(2x^2-5x-3)=0 equation:


Simplifying
(7x + 2)(2x2 + -5x + -3) = 0

Reorder the terms:
(2 + 7x)(2x2 + -5x + -3) = 0

Reorder the terms:
(2 + 7x)(-3 + -5x + 2x2) = 0

Multiply (2 + 7x) * (-3 + -5x + 2x2)
(2(-3 + -5x + 2x2) + 7x * (-3 + -5x + 2x2)) = 0
((-3 * 2 + -5x * 2 + 2x2 * 2) + 7x * (-3 + -5x + 2x2)) = 0
((-6 + -10x + 4x2) + 7x * (-3 + -5x + 2x2)) = 0
(-6 + -10x + 4x2 + (-3 * 7x + -5x * 7x + 2x2 * 7x)) = 0
(-6 + -10x + 4x2 + (-21x + -35x2 + 14x3)) = 0

Reorder the terms:
(-6 + -10x + -21x + 4x2 + -35x2 + 14x3) = 0

Combine like terms: -10x + -21x = -31x
(-6 + -31x + 4x2 + -35x2 + 14x3) = 0

Combine like terms: 4x2 + -35x2 = -31x2
(-6 + -31x + -31x2 + 14x3) = 0

Solving
-6 + -31x + -31x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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